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修复RealtimeCollisions.intersectMovingCircleBox计算问题

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This commit is contained in:
yhh
2020-12-09 17:56:48 +08:00
parent 838795fd34
commit 24da0b79c2
6 changed files with 54 additions and 37 deletions
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40
source/bin/framework.js
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@@ -4214,12 +4214,14 @@ var TimeUtils = /** @class */ (function () {
}());
var es;
(function (es) {
/** 贝塞尔帮助类 */
/**
* 三次方和二次方贝塞尔帮助器(cubic and quadratic bezier helper)
*/
var Bezier = /** @class */ (function () {
function Bezier() {
}
/**
* 二次贝塞尔曲线
* 求解二次曲折线
* @param p0
* @param p1
* @param p2
@@ -5886,7 +5888,7 @@ var es;
var Collisions = /** @class */ (function () {
function Collisions() {
}
Collisions.isLineToLine = function (a1, a2, b1, b2) {
Collisions.lineToLine = function (a1, a2, b1, b2) {
var b = es.Vector2.subtract(a2, a1);
var d = es.Vector2.subtract(b2, b1);
var bDotDPerp = b.x * d.y - b.y * d.x;
@@ -5902,23 +5904,27 @@ var es;
return false;
return true;
};
Collisions.lineToLineIntersection = function (a1, a2, b1, b2) {
var intersection = es.Vector2.zero;
Collisions.lineToLineIntersection = function (a1, a2, b1, b2, intersection) {
if (intersection === void 0) { intersection = new es.Vector2(); }
intersection.x = 0;
intersection.y = 0;
var b = es.Vector2.subtract(a2, a1);
var d = es.Vector2.subtract(b2, b1);
var bDotDPerp = b.x * d.y - b.y * d.x;
// 如果b*d = 0，表示这两条直线平行，因此有无穷个交点
if (bDotDPerp == 0)
return intersection;
return false;
var c = es.Vector2.subtract(b1, a1);
var t = (c.x * d.y - c.y * d.x) / bDotDPerp;
if (t < 0 || t > 1)
return intersection;
return false;
var u = (c.x * b.y - c.y * b.x) / bDotDPerp;
if (u < 0 || u > 1)
return intersection;
intersection = es.Vector2.add(a1, new es.Vector2(t * b.x, t * b.y));
return intersection;
return false;
var temp = es.Vector2.add(a1, new es.Vector2(t * b.x, t * b.y));
intersection.x = temp.x;
intersection.y = temp.y;
return true;
};
Collisions.closestPointOnLine = function (lineA, lineB, closestTo) {
var v = es.Vector2.subtract(lineB, lineA);
@@ -5937,8 +5943,10 @@ var es;
return es.Vector2.distanceSquared(circleCenter, point) < radius * radius;
};
Collisions.rectToCircle = function (rect, cPosition, cRadius) {
// 检查矩形是否包含圆的中心点
if (this.rectToPoint(rect.x, rect.y, rect.width, rect.height, cPosition))
return true;
// 对照相关边缘检查圆圈
var edgeFrom;
var edgeTo;
var sector = this.getSector(rect.x, rect.y, rect.width, rect.height, cPosition);
@@ -5985,25 +5993,25 @@ var es;
if ((both & PointSectors.top) != 0) {
edgeFrom = new es.Vector2(rect.x, rect.y);
edgeTo = new es.Vector2(rect.x + rect.width, rect.y);
if (this.isLineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
if (this.lineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
return true;
}
if ((both & PointSectors.bottom) != 0) {
edgeFrom = new es.Vector2(rect.x, rect.y + rect.height);
edgeTo = new es.Vector2(rect.x + rect.width, rect.y + rect.height);
if (this.isLineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
if (this.lineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
return true;
}
if ((both & PointSectors.left) != 0) {
edgeFrom = new es.Vector2(rect.x, rect.y);
edgeTo = new es.Vector2(rect.x, rect.y + rect.height);
if (this.isLineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
if (this.lineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
return true;
}
if ((both & PointSectors.right) != 0) {
edgeFrom = new es.Vector2(rect.x + rect.width, rect.y);
edgeTo = new es.Vector2(rect.x + rect.width, rect.y + rect.height);
if (this.isLineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
if (this.lineToLine(edgeFrom, edgeTo, lineFrom, lineTo))
return true;
}
}
@@ -7061,14 +7069,14 @@ var es;
}
RealtimeCollisions.intersectMovingCircleBox = function (s, b, movement, time) {
// 计算将b按球面半径r扩大后的AABB
var e = b.bounds;
var e = b.bounds.clone();
e.inflate(s.radius, s.radius);
// 将射线与展开的矩形e相交，如果射线错过了e，则以无交点退出，否则得到交点p和时间t作为结果。
var ray = new es.Ray2D(es.Vector2.subtract(s.position, movement), s.position);
if (!e.rayIntersects(ray, time) && time.value > 1)
return false;
// 求交点
var point = es.Vector2.add(ray.start, es.Vector2.add(ray.direction, new es.Vector2(time.value)));
var point = es.Vector2.add(ray.start, es.Vector2.multiply(ray.direction, new es.Vector2(time.value)));
// 计算交点p位于b的哪个最小面和最大面之外。注意，u和v不能有相同的位集，它们之间必须至少有一个位集。
var u, v = 0;
if (point.x < b.bounds.left)